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How does Ruby resolve a method call through the ancestor chain?

Peer-reviewed by HireXTech Technical Panel Updated for 2025/2026 hiring Editorial standards
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Interviewer Expectations for this Question
01
Core Competency

Assesses fundamental understanding of Ruby conventions, runtime behavior, and memory/performance considerations.

02
Evaluation Criteria

Hiring managers look for precision, avoidance of ambiguous jargon, and ability to explain trade-offs under real production conditions.

Comprehensive Model Answer Verified Solution

Ruby resolves a call by walking the receiver's singleton class, then the class, then included modules and superclasses, in order. Module#ancestors prints the chain.

module A; def hi = "A"; end
module B; def hi = "B"; end

class C
  prepend A
  include B
end

C.ancestors # [A, C, B, Object, Kernel, BasicObject]
C.new.hi    # "A"

Key rules: prepend places a module before the class, while include places it after. Among included modules the last one included comes first. Singleton methods beat instance methods, and super continues the search from the next entry in the chain.

method_missing is the last resort before NoMethodError, and respond_to? should be kept consistent with it. Refinements can scope overrides lexically. This chain is why prepended modules and concerns are powerful, and why ordering matters when several mixins define the same method.

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