React Easy technical 1 views 1 min read

What is the difference between `super()` and `super(props)` in React using ES6 classes?

Peer-reviewed by HireXTech Technical Panel Updated for 2025/2026 hiring Editorial standards
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Interviewer Expectations for this Question
01
Core Competency

Assesses fundamental understanding of React conventions, runtime behavior, and memory/performance considerations.

02
Evaluation Criteria

Hiring managers look for precision, avoidance of ambiguous jargon, and ability to explain trade-offs under real production conditions.

Comprehensive Model Answer Verified Solution

When you want to access this.props in constructor() then you should pass props to super() method.

Using super(props):

    class MyComponent extends React.Component {
      constructor(props) {
        super(props);
        console.log(this.props); // { name: 'John', ... }
      }
    }
    

Using super():

    class MyComponent extends React.Component {
      constructor(props) {
        super();
        console.log(this.props); // undefined
      }
    }
    

Outside constructor() both will display same value for this.props.

Candidate Response Strategy & Interview Tips

  1. Start with a concise one-sentence summary: Deliver a direct, confident answer first before expanding into nuances.
  2. Demonstrate real-world trade-offs: Discuss where this approach excels and when you would avoid it in production systems.
  3. Discuss complexity & edge cases: Proactively explain time/space complexity or boundary conditions (null values, scale limits).
  4. Prepare for interviewer follow-ups: Technical hiring panels frequently probe deeper into concurrency, backward compatibility, or alternative libraries.
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